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1100111001257 is a prime number
BaseRepresentation
bin10000000000100011101…
…110011011011010101001
310220011120121221012211102
4100000203232123122221
5121011011404020012
62201214540411145
7142323530136242
oct20004356333251
93804517835742
101100111001257
11394610a86974
12159260b46ab5
137c980aa12a8
143b36211dcc9
151d93a5ca2c2
hex10023b9b6a9

1100111001257 has 2 divisors, whose sum is σ = 1100111001258. Its totient is φ = 1100111001256.

The previous prime is 1100111001217. The next prime is 1100111001259. The reversal of 1100111001257 is 7521001110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 780234789481 + 319876211776 = 883309^2 + 565576^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100111001257 - 214 = 1100110984873 is a prime.

Together with 1100111001259, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1100111001259) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055500628 + 550055500629.

It is an arithmetic number, because the mean of its divisors is an integer number (550055500629).

Almost surely, 21100111001257 is an apocalyptic number.

It is an amenable number.

1100111001257 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100111001257 is an equidigital number, since it uses as much as digits as its factorization.

1100111001257 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 70, while the sum is 20.

Adding to 1100111001257 its reverse (7521001110011), we get a palindrome (8621112111268).

The spelling of 1100111001257 in words is "one trillion, one hundred billion, one hundred eleven million, one thousand, two hundred fifty-seven".