Base | Representation |
---|---|
bin | 10000000000100011101… |
… | …110011011011010101001 |
3 | 10220011120121221012211102 |
4 | 100000203232123122221 |
5 | 121011011404020012 |
6 | 2201214540411145 |
7 | 142323530136242 |
oct | 20004356333251 |
9 | 3804517835742 |
10 | 1100111001257 |
11 | 394610a86974 |
12 | 159260b46ab5 |
13 | 7c980aa12a8 |
14 | 3b36211dcc9 |
15 | 1d93a5ca2c2 |
hex | 10023b9b6a9 |
1100111001257 has 2 divisors, whose sum is σ = 1100111001258. Its totient is φ = 1100111001256.
The previous prime is 1100111001217. The next prime is 1100111001259. The reversal of 1100111001257 is 7521001110011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 780234789481 + 319876211776 = 883309^2 + 565576^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100111001257 - 214 = 1100110984873 is a prime.
Together with 1100111001259, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1100111001259) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550055500628 + 550055500629.
It is an arithmetic number, because the mean of its divisors is an integer number (550055500629).
Almost surely, 21100111001257 is an apocalyptic number.
It is an amenable number.
1100111001257 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100111001257 is an equidigital number, since it uses as much as digits as its factorization.
1100111001257 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 70, while the sum is 20.
Adding to 1100111001257 its reverse (7521001110011), we get a palindrome (8621112111268).
The spelling of 1100111001257 in words is "one trillion, one hundred billion, one hundred eleven million, one thousand, two hundred fifty-seven".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.071 sec. • engine limits •