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11001110501483 is a prime number
BaseRepresentation
bin1010000000010110010101…
…0010001001100001101011
31102221200210022020222221222
42200011211102021201223
52420220233242021413
635221501305252255
72213542526245064
oct240054522114153
942850708228858
1011001110501483
1135615aa097133
12129810979408b
1361a52851091b
142a0656c4956b
1514126de16b08
hexa016548986b

11001110501483 has 2 divisors, whose sum is σ = 11001110501484. Its totient is φ = 11001110501482.

The previous prime is 11001110501477. The next prime is 11001110501573. The reversal of 11001110501483 is 38410501110011.

It is a weak prime.

It is an emirp because it is prime and its reverse (38410501110011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001110501483 - 210 = 11001110500459 is a prime.

It is not a weakly prime, because it can be changed into another prime (11001110501683) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555250741 + 5500555250742.

It is an arithmetic number, because the mean of its divisors is an integer number (5500555250742).

Almost surely, 211001110501483 is an apocalyptic number.

11001110501483 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001110501483 is an equidigital number, since it uses as much as digits as its factorization.

11001110501483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 480, while the sum is 26.

Adding to 11001110501483 its reverse (38410501110011), we get a palindrome (49411611611494).

The spelling of 11001110501483 in words is "eleven trillion, one billion, one hundred ten million, five hundred one thousand, four hundred eighty-three".