Base | Representation |
---|---|
bin | 10100011111011011… |
… | …11010000111000111 |
3 | 1001101200112100012221 |
4 | 22033231322013013 |
5 | 140012241022413 |
6 | 5015343553211 |
7 | 536421620602 |
oct | 121755720707 |
9 | 31350470187 |
10 | 11001110983 |
11 | 4735927565 |
12 | 21702bb807 |
13 | 1064226235 |
14 | 7650bd339 |
15 | 445c0d68d |
hex | 28fb7a1c7 |
11001110983 has 2 divisors, whose sum is σ = 11001110984. Its totient is φ = 11001110982.
The previous prime is 11001110963. The next prime is 11001111041. The reversal of 11001110983 is 38901110011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001110983 - 217 = 11000979911 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001110963) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555491 + 5500555492.
It is an arithmetic number, because the mean of its divisors is an integer number (5500555492).
Almost surely, 211001110983 is an apocalyptic number.
11001110983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001110983 is an equidigital number, since it uses as much as digits as its factorization.
11001110983 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 25.
Adding to 11001110983 its reverse (38901110011), we get a palindrome (49902220994).
The spelling of 11001110983 in words is "eleven billion, one million, one hundred ten thousand, nine hundred eighty-three".
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