Base | Representation |
---|---|
bin | 1010000000010110010101… |
… | …0100011100011010110111 |
3 | 1102221200210100101120022021 |
4 | 2200011211110130122313 |
5 | 2420220233420300114 |
6 | 35221501330214011 |
7 | 2213542534332202 |
oct | 240054524343267 |
9 | 42850710346267 |
10 | 11001111103159 |
11 | 35615aa468191 |
12 | 1298109a24307 |
13 | 61a528691748 |
14 | 2a0656d64939 |
15 | 14126ded5024 |
hex | a016551c6b7 |
11001111103159 has 2 divisors, whose sum is σ = 11001111103160. Its totient is φ = 11001111103158.
The previous prime is 11001111103153. The next prime is 11001111103249. The reversal of 11001111103159 is 95130111110011.
It is a weak prime.
It is an emirp because it is prime and its reverse (95130111110011) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11001111103159 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001111103153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500555551579 + 5500555551580.
It is an arithmetic number, because the mean of its divisors is an integer number (5500555551580).
Almost surely, 211001111103159 is an apocalyptic number.
11001111103159 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001111103159 is an equidigital number, since it uses as much as digits as its factorization.
11001111103159 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135, while the sum is 25.
The spelling of 11001111103159 in words is "eleven trillion, one billion, one hundred eleven million, one hundred three thousand, one hundred fifty-nine".
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