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11001111113 = 14401763913
BaseRepresentation
bin10100011111011011…
…11010001001001001
31001101200112100101202
422033231322021021
5140012241023423
65015343553545
7536421621146
oct121755721111
931350470352
1011001111113
114735927673
1221702bb8b5
131064226305
147650bd3cd
15445c0d728
hex28fb7a249

11001111113 has 4 divisors (see below), whose sum is σ = 11001889428. Its totient is φ = 11000332800.

The previous prime is 11001111101. The next prime is 11001111119. The reversal of 11001111113 is 31111110011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 5862658624 + 5138452489 = 76568^2 + 71683^2 .

It is a cyclic number.

It is not a de Polignac number, because 11001111113 - 222 = 10996916809 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11001111094 and 11001111103.

It is not an unprimeable number, because it can be changed into a prime (11001111119) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 367556 + ... + 396357.

It is an arithmetic number, because the mean of its divisors is an integer number (2750472357).

Almost surely, 211001111113 is an apocalyptic number.

It is an amenable number.

11001111113 is a deficient number, since it is larger than the sum of its proper divisors (778315).

11001111113 is an equidigital number, since it uses as much as digits as its factorization.

11001111113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 778314.

The product of its (nonzero) digits is 3, while the sum is 11.

Adding to 11001111113 its reverse (31111110011), we get a palindrome (42112221124).

The spelling of 11001111113 in words is "eleven billion, one million, one hundred eleven thousand, one hundred thirteen".

Divisors: 1 14401 763913 11001111113