110011202120143 has 2 divisors, whose sum is σ = 110011202120144. Its totient is φ = 110011202120142.

The previous prime is 110011202120087. The next prime is 110011202120251. The reversal of 110011202120143 is 341021202110011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110011202120143 - 2¹⁷ = 110011201989071 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 110011202120143.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011202121143) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005601060071 + 55005601060072.

It is an arithmetic number, because the mean of its divisors is an integer number (55005601060072).

Almost surely, 2^{110011202120143} is an apocalyptic number.

110011202120143 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011202120143 is an equidigital number, since it uses as much as digits as its factorization.

110011202120143 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 110011202120143 its reverse (341021202110011), we get a palindrome (451032404230154).

The spelling of 110011202120143 in words is "one hundred ten trillion, eleven billion, two hundred two million, one hundred twenty thousand, one hundred forty-three".