11001121212113 has 4 divisors (see below), whose sum is σ = 11001708176448. Its totient is φ = 11000534247780.

The previous prime is 11001121212097. The next prime is 11001121212131. The reversal of 11001121212113 is 31121212110011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11001121212113 - 2⁴ = 11001121212097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11001121212091 and 11001121212100.

It is not an unprimeable number, because it can be changed into a prime (11001121212013) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 293454053 + ... + 293491538.

It is an arithmetic number, because the mean of its divisors is an integer number (2750427044112).

Almost surely, 2^{11001121212113} is an apocalyptic number.

It is an amenable number.

11001121212113 is a deficient number, since it is larger than the sum of its proper divisors (586964335).

11001121212113 is an equidigital number, since it uses as much as digits as its factorization.

11001121212113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 586964334.

The product of its (nonzero) digits is 24, while the sum is 17.

Adding to 11001121212113 its reverse (31121212110011), we get a palindrome (42122333322124).

The spelling of 11001121212113 in words is "eleven trillion, one billion, one hundred twenty-one million, two hundred twelve thousand, one hundred thirteen".