110011219973 has 2 divisors, whose sum is σ = 110011219974. Its totient is φ = 110011219972.

The previous prime is 110011219939. The next prime is 110011219979. The reversal of 110011219973 is 379912110011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 88841551969 + 21169668004 = 298063^2 + 145498^2 .

It is a cyclic number.

It is not a de Polignac number, because 110011219973 - 2¹⁰ = 110011218949 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110011219979) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005609986 + 55005609987.

It is an arithmetic number, because the mean of its divisors is an integer number (55005609987).

Almost surely, 2^110011219973 is an apocalyptic number.

It is an amenable number.

110011219973 is a deficient number, since it is larger than the sum of its proper divisors (1).

110011219973 is an equidigital number, since it uses as much as digits as its factorization.

110011219973 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402, while the sum is 35.

Adding to 110011219973 its reverse (379912110011), we get a palindrome (489923329984).

The spelling of 110011219973 in words is "one hundred ten billion, eleven million, two hundred nineteen thousand, nine hundred seventy-three".