Base | Representation |
---|---|
bin | 10000000000100011110… |
… | …011110100010100100101 |
3 | 10220011120201120222201211 |
4 | 100000203303310110211 |
5 | 121011012234221424 |
6 | 2201215030551421 |
7 | 142323545142061 |
oct | 20004363642445 |
9 | 3804521528654 |
10 | 1100112413989 |
11 | 394611861316 |
12 | 159261508571 |
13 | 7c981177324 |
14 | 3b3623aaaa1 |
15 | 1d93a7a8b94 |
hex | 10023cf4525 |
1100112413989 has 2 divisors, whose sum is σ = 1100112413990. Its totient is φ = 1100112413988.
The previous prime is 1100112413971. The next prime is 1100112414013. The reversal of 1100112413989 is 9893142110011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 782929437889 + 317182976100 = 884833^2 + 563190^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100112413989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100112413909) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550056206994 + 550056206995.
It is an arithmetic number, because the mean of its divisors is an integer number (550056206995).
Almost surely, 21100112413989 is an apocalyptic number.
It is an amenable number.
1100112413989 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100112413989 is an equidigital number, since it uses as much as digits as its factorization.
1100112413989 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15552, while the sum is 40.
The spelling of 1100112413989 in words is "one trillion, one hundred billion, one hundred twelve million, four hundred thirteen thousand, nine hundred eighty-nine".
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