Base | Representation |
---|---|
bin | 11001000000110111111101… |
… | …001000100110000110111111 |
3 | 112102111222020202120102111011 |
4 | 121000313331020212012333 |
5 | 103404411012011210333 |
6 | 1025550245022540051 |
7 | 32113023121141354 |
oct | 3100677510460677 |
9 | 472458222512434 |
10 | 110011244241343 |
11 | 32064563429135 |
12 | 10408abb137627 |
13 | 49500289a32c3 |
14 | 1d2480342c62b |
15 | cab9a19499cd |
hex | 640dfd2261bf |
110011244241343 has 4 divisors (see below), whose sum is σ = 110364978145968. Its totient is φ = 109657510336720.
The previous prime is 110011244241341. The next prime is 110011244241361. The reversal of 110011244241343 is 343142442110011.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 110011244241343 - 21 = 110011244241341 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110011244241341) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 176866951846 + ... + 176866952467.
It is an arithmetic number, because the mean of its divisors is an integer number (27591244536492).
Almost surely, 2110011244241343 is an apocalyptic number.
110011244241343 is a deficient number, since it is larger than the sum of its proper divisors (353733904625).
110011244241343 is an equidigital number, since it uses as much as digits as its factorization.
110011244241343 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 353733904624.
The product of its (nonzero) digits is 9216, while the sum is 31.
Adding to 110011244241343 its reverse (343142442110011), we get a palindrome (453153686351354).
The spelling of 110011244241343 in words is "one hundred ten trillion, eleven billion, two hundred forty-four million, two hundred forty-one thousand, three hundred forty-three".
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