Base | Representation |
---|---|
bin | 1010000000010110011100… |
… | …1110001101001010101011 |
3 | 1102221200212120110020001212 |
4 | 2200011213032031022223 |
5 | 2420220320103203001 |
6 | 35221504430303335 |
7 | 2213543402542604 |
oct | 240054716151253 |
9 | 42850776406055 |
10 | 11001143022251 |
11 | 35616164894a8 |
12 | 1298118657b4b |
13 | 61a532189095 |
14 | 2a065b2b2dab |
15 | 141271bdc7bb |
hex | a016738d2ab |
11001143022251 has 2 divisors, whose sum is σ = 11001143022252. Its totient is φ = 11001143022250.
The previous prime is 11001143022203. The next prime is 11001143022263. The reversal of 11001143022251 is 15222034110011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11001143022251 - 230 = 11000069280427 is a prime.
It is a super-2 number, since 2×110011430222512 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11001143522251) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500571511125 + 5500571511126.
It is an arithmetic number, because the mean of its divisors is an integer number (5500571511126).
Almost surely, 211001143022251 is an apocalyptic number.
11001143022251 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001143022251 is an equidigital number, since it uses as much as digits as its factorization.
11001143022251 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 480, while the sum is 23.
Adding to 11001143022251 its reverse (15222034110011), we get a palindrome (26223177132262).
The spelling of 11001143022251 in words is "eleven trillion, one billion, one hundred forty-three million, twenty-two thousand, two hundred fifty-one".
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