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1100114343401 is a prime number
BaseRepresentation
bin10000000000100011111…
…011001011010111101001
310220011120212020000101112
4100000203323023113221
5121011013232442101
62201215140200105
7142323600426143
oct20004373132751
93804525200345
101100114343401
11394612959977
12159262099035
137c9816a15a8
143b36274dc93
151d93aa3a6bb
hex10023ecb5e9

1100114343401 has 2 divisors, whose sum is σ = 1100114343402. Its totient is φ = 1100114343400.

The previous prime is 1100114343389. The next prime is 1100114343431. The reversal of 1100114343401 is 1043434110011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1076613760000 + 23500583401 = 1037600^2 + 153299^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100114343401 - 26 = 1100114343337 is a prime.

It is a super-2 number, since 2×11001143434012 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100114343431) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550057171700 + 550057171701.

It is an arithmetic number, because the mean of its divisors is an integer number (550057171701).

Almost surely, 21100114343401 is an apocalyptic number.

It is an amenable number.

1100114343401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100114343401 is an equidigital number, since it uses as much as digits as its factorization.

1100114343401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 576, while the sum is 23.

Adding to 1100114343401 its reverse (1043434110011), we get a palindrome (2143548453412).

The spelling of 1100114343401 in words is "one trillion, one hundred billion, one hundred fourteen million, three hundred forty-three thousand, four hundred one".