11001151431217 has 2 divisors, whose sum is σ = 11001151431218. Its totient is φ = 11001151431216.

The previous prime is 11001151431181. The next prime is 11001151431253. The reversal of 11001151431217 is 71213415110011.

It is a balanced prime because it is at equal distance from previous prime (11001151431181) and next prime (11001151431253).

It can be written as a sum of positive squares in only one way, i.e., 10985406451776 + 15744979441 = 3314424^2 + 125479^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-11001151431217 is a prime.

It is not a weakly prime, because it can be changed into another prime (11001151431287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500575715608 + 5500575715609.

It is an arithmetic number, because the mean of its divisors is an integer number (5500575715609).

Almost surely, 2^{11001151431217} is an apocalyptic number.

It is an amenable number.

11001151431217 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001151431217 is an equidigital number, since it uses as much as digits as its factorization.

11001151431217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 840, while the sum is 28.

Adding to 11001151431217 its reverse (71213415110011), we get a palindrome (82214566541228).

The spelling of 11001151431217 in words is "eleven trillion, one billion, one hundred fifty-one million, four hundred thirty-one thousand, two hundred seventeen".