110012010083 has 2 divisors, whose sum is σ = 110012010084. Its totient is φ = 110012010082.

The previous prime is 110012010011. The next prime is 110012010131. The reversal of 110012010083 is 380010210011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 110012010083 - 2¹⁰ = 110012009059 is a prime.

It is a super-3 number, since 3×110012010083³ (a number of 34 digits) contains 333 as substring.

It is not a weakly prime, because it can be changed into another prime (110012010683) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006005041 + 55006005042.

It is an arithmetic number, because the mean of its divisors is an integer number (55006005042).

Almost surely, 2^110012010083 is an apocalyptic number.

110012010083 is a deficient number, since it is larger than the sum of its proper divisors (1).

110012010083 is an equidigital number, since it uses as much as digits as its factorization.

110012010083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 110012010083 its reverse (380010210011), we get a palindrome (490022220094).

The spelling of 110012010083 in words is "one hundred ten billion, twelve million, ten thousand, eighty-three".