Base | Representation |
---|---|
bin | 10100011111011100… |
… | …10000010100111111 |
3 | 1001101200200222001022 |
4 | 22033232100110333 |
5 | 140012301430413 |
6 | 5015345534355 |
7 | 536422450112 |
oct | 121756202477 |
9 | 31350628038 |
10 | 11001201983 |
11 | 4735989972 |
12 | 21703443bb |
13 | 1064258795 |
14 | 765104579 |
15 | 445c2a608 |
hex | 28fb9053f |
11001201983 has 2 divisors, whose sum is σ = 11001201984. Its totient is φ = 11001201982.
The previous prime is 11001201977. The next prime is 11001202021. The reversal of 11001201983 is 38910210011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11001201983 - 212 = 11001197887 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001201923) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500600991 + 5500600992.
It is an arithmetic number, because the mean of its divisors is an integer number (5500600992).
Almost surely, 211001201983 is an apocalyptic number.
11001201983 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001201983 is an equidigital number, since it uses as much as digits as its factorization.
11001201983 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 432, while the sum is 26.
Adding to 11001201983 its reverse (38910210011), we get a palindrome (49911411994).
The spelling of 11001201983 in words is "eleven billion, one million, two hundred one thousand, nine hundred eighty-three".
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