Base | Representation |
---|---|
bin | 1010000000010110101011… |
… | …0100001111001000010110 |
3 | 1102221201000202220211201021 |
4 | 2200011222310033020112 |
5 | 2420220431022322124 |
6 | 35221514422551354 |
7 | 2213545034233003 |
oct | 240055264171026 |
9 | 42851022824637 |
10 | 11001203323414 |
11 | 3561647525677 |
12 | 129813489855a |
13 | 61a541810145 |
14 | 2a06652cc8aa |
15 | 14127714e7e4 |
hex | a016ad0f216 |
11001203323414 has 4 divisors (see below), whose sum is σ = 16501804985124. Its totient is φ = 5500601661706.
The previous prime is 11001203323381. The next prime is 11001203323423. The reversal of 11001203323414 is 41432330210011.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750300830852 + ... + 2750300830855.
It is an arithmetic number, because the mean of its divisors is an integer number (4125451246281).
Almost surely, 211001203323414 is an apocalyptic number.
11001203323414 is a deficient number, since it is larger than the sum of its proper divisors (5500601661710).
11001203323414 is an equidigital number, since it uses as much as digits as its factorization.
11001203323414 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5500601661709.
The product of its (nonzero) digits is 1728, while the sum is 25.
Adding to 11001203323414 its reverse (41432330210011), we get a palindrome (52433533533425).
The spelling of 11001203323414 in words is "eleven trillion, one billion, two hundred three million, three hundred twenty-three thousand, four hundred fourteen".
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