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110012101000033 is a prime number
BaseRepresentation
bin11001000000111000110000…
…001100110111101101100001
3112102112001110110201021110111
4121000320300030313231201
5103404414240324000113
61025550510030131321
732113053263362201
oct3100706014675541
9472461413637414
10110012101000033
1132064963006671
12104090ba050b41
1349501343399cb
141d24885130401
15caba01c8413d
hex640e30337b61

110012101000033 has 2 divisors, whose sum is σ = 110012101000034. Its totient is φ = 110012101000032.

The previous prime is 110012100999971. The next prime is 110012101000049. The reversal of 110012101000033 is 330000101210011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64645571821009 + 45366529179024 = 8040247^2 + 6735468^2 .

It is a cyclic number.

It is not a de Polignac number, because 110012101000033 - 217 = 110012100868961 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110012100999977 and 110012101000022.

It is not a weakly prime, because it can be changed into another prime (110012101000733) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006050500016 + 55006050500017.

It is an arithmetic number, because the mean of its divisors is an integer number (55006050500017).

Almost surely, 2110012101000033 is an apocalyptic number.

It is an amenable number.

110012101000033 is a deficient number, since it is larger than the sum of its proper divisors (1).

110012101000033 is an equidigital number, since it uses as much as digits as its factorization.

110012101000033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 110012101000033 its reverse (330000101210011), we get a palindrome (440012202210044).

The spelling of 110012101000033 in words is "one hundred ten trillion, twelve billion, one hundred one million, thirty-three", and thus it is an aban number.