Base | Representation |
---|---|
bin | 11001000000111000110110… |
… | …001110100010100100111011 |
3 | 112102112001201111221201222122 |
4 | 121000320312032202210323 |
5 | 103404414442214213201 |
6 | 1025550524041111455 |
7 | 32113055631621305 |
oct | 3100706616424473 |
9 | 472461644851878 |
10 | 110012202101051 |
11 | 32064a0508a328 |
12 | 10409127a8858b |
13 | 495014c2776b3 |
14 | 1d2489472a975 |
15 | caba0aaa4e1b |
hex | 640e363a293b |
110012202101051 has 2 divisors, whose sum is σ = 110012202101052. Its totient is φ = 110012202101050.
The previous prime is 110012202100979. The next prime is 110012202101063. The reversal of 110012202101051 is 150101202210011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110012202101051 - 234 = 109995022231867 is a prime.
It is a super-2 number, since 2×1100122021010512 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110012202101551) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006101050525 + 55006101050526.
It is an arithmetic number, because the mean of its divisors is an integer number (55006101050526).
Almost surely, 2110012202101051 is an apocalyptic number.
110012202101051 is a deficient number, since it is larger than the sum of its proper divisors (1).
110012202101051 is an equidigital number, since it uses as much as digits as its factorization.
110012202101051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 110012202101051 its reverse (150101202210011), we get a palindrome (260113404311062).
The spelling of 110012202101051 in words is "one hundred ten trillion, twelve billion, two hundred two million, one hundred one thousand, fifty-one".
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