Base | Representation |
---|---|
bin | 11001000000111000110110… |
… | …111000111011100010001011 |
3 | 112102112001202021212022011021 |
4 | 121000320312320323202023 |
5 | 103404420003040311243 |
6 | 1025550525115213311 |
7 | 32113056125232511 |
oct | 3100706670734213 |
9 | 472461667768137 |
10 | 110012213213323 |
11 | 32064a1038a123 |
12 | 1040912b747237 |
13 | 49501516685c5 |
14 | 1d24895dc04b1 |
15 | caba0ba4c6ed |
hex | 640e36e3b88b |
110012213213323 has 2 divisors, whose sum is σ = 110012213213324. Its totient is φ = 110012213213322.
The previous prime is 110012213213297. The next prime is 110012213213449. The reversal of 110012213213323 is 323312312210011.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110012213213323 is a prime.
It is not a weakly prime, because it can be changed into another prime (110012213243323) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006106606661 + 55006106606662.
It is an arithmetic number, because the mean of its divisors is an integer number (55006106606662).
Almost surely, 2110012213213323 is an apocalyptic number.
110012213213323 is a deficient number, since it is larger than the sum of its proper divisors (1).
110012213213323 is an equidigital number, since it uses as much as digits as its factorization.
110012213213323 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1296, while the sum is 25.
Adding to 110012213213323 its reverse (323312312210011), we get a palindrome (433324525423334).
The spelling of 110012213213323 in words is "one hundred ten trillion, twelve billion, two hundred thirteen million, two hundred thirteen thousand, three hundred twenty-three".
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