Base | Representation |
---|---|
bin | 10100011111011101… |
… | …01000011000011101 |
3 | 1001101200212222012102 |
4 | 22033232220120131 |
5 | 140012313104014 |
6 | 5015352014445 |
7 | 536423340263 |
oct | 121756503035 |
9 | 31350788172 |
10 | 11001300509 |
11 | 4735a469a1 |
12 | 2170391425 |
13 | 1064291594 |
14 | 76512c433 |
15 | 445c498de |
hex | 28fba861d |
11001300509 has 2 divisors, whose sum is σ = 11001300510. Its totient is φ = 11001300508.
The previous prime is 11001300473. The next prime is 11001300521. The reversal of 11001300509 is 90500310011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8533694884 + 2467605625 = 92378^2 + 49675^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001300509 - 212 = 11001296413 is a prime.
It is a super-2 number, since 2×110013005092 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11001300589) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500650254 + 5500650255.
It is an arithmetic number, because the mean of its divisors is an integer number (5500650255).
Almost surely, 211001300509 is an apocalyptic number.
It is an amenable number.
11001300509 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001300509 is an equidigital number, since it uses as much as digits as its factorization.
11001300509 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 135, while the sum is 20.
The spelling of 11001300509 in words is "eleven billion, one million, three hundred thousand, five hundred nine".
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