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110013030119 is a prime number
BaseRepresentation
bin110011001110101001…
…0011001111011100111
3101111221222220222100002
41212131102121323213
53300301313430434
6122312253011515
710643140220066
oct1463522317347
9344858828302
10110013030119
114272453a903
12193a3183b9b
13a4b310ca35
145478c161dd
152cdd31d57e
hex199d499ee7

110013030119 has 2 divisors, whose sum is σ = 110013030120. Its totient is φ = 110013030118.

The previous prime is 110013030059. The next prime is 110013030131. The reversal of 110013030119 is 911030310011.

It is a strong prime.

It is an emirp because it is prime and its reverse (911030310011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 110013030119 - 212 = 110013026023 is a prime.

It is a super-2 number, since 2×1100130301192 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 110013030119.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110013030719) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006515059 + 55006515060.

It is an arithmetic number, because the mean of its divisors is an integer number (55006515060).

Almost surely, 2110013030119 is an apocalyptic number.

110013030119 is a deficient number, since it is larger than the sum of its proper divisors (1).

110013030119 is an equidigital number, since it uses as much as digits as its factorization.

110013030119 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 20.

The spelling of 110013030119 in words is "one hundred ten billion, thirteen million, thirty thousand, one hundred nineteen".