11001310111999 has 2 divisors, whose sum is σ = 11001310112000. Its totient is φ = 11001310111998.

The previous prime is 11001310111993. The next prime is 11001310112029. The reversal of 11001310111999 is 99911101310011.

11001310111999 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It is an emirp because it is prime and its reverse (99911101310011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11001310111999 - 2³ = 11001310111991 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11001310111991) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500655055999 + 5500655056000.

It is an arithmetic number, because the mean of its divisors is an integer number (5500655056000).

Almost surely, 2^{11001310111999} is an apocalyptic number.

11001310111999 is a deficient number, since it is larger than the sum of its proper divisors (1).

11001310111999 is an equidigital number, since it uses as much as digits as its factorization.

11001310111999 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2187, while the sum is 37.

The spelling of 11001310111999 in words is "eleven trillion, one billion, three hundred ten million, one hundred eleven thousand, nine hundred ninety-nine".