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11001311112013 = 41789926325287
BaseRepresentation
bin1010000000010111000100…
…1111011010101101001101
31102221201022021202001212121
42200011301033122231031
52420221141121041023
635221533233132541
72213550513354325
oct240056117325515
942851267661777
1011001311112013
1135616a2356862
1212981649ba151
1361a55ac4ca91
142a067574a285
15141281841d5d
hexa01713dab4d

11001311112013 has 4 divisors (see below), whose sum is σ = 11001337855200. Its totient is φ = 11001284368828.

The previous prime is 11001311111963. The next prime is 11001311112037. The reversal of 11001311112013 is 31021111310011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-11001311112013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11001311112613) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12744745 + ... + 13580542.

It is an arithmetic number, because the mean of its divisors is an integer number (2750334463800).

Almost surely, 211001311112013 is an apocalyptic number.

It is an amenable number.

11001311112013 is a deficient number, since it is larger than the sum of its proper divisors (26743187).

11001311112013 is an equidigital number, since it uses as much as digits as its factorization.

11001311112013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26743186.

The product of its (nonzero) digits is 18, while the sum is 16.

Adding to 11001311112013 its reverse (31021111310011), we get a palindrome (42022422422024).

The spelling of 11001311112013 in words is "eleven trillion, one billion, three hundred eleven million, one hundred twelve thousand, thirteen".

Divisors: 1 417899 26325287 11001311112013