110013113330023 has 4 divisors (see below), whose sum is σ = 110410272584200. Its totient is φ = 109615954075848.

The previous prime is 110013113330011. The next prime is 110013113330047. The reversal of 110013113330023 is 320033311310011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 110013113330023 - 2⁵ = 110013113329991 is a prime.

It is a super-2 number, since 2×110013113330023² (a number of 29 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110013113329976 and 110013113330003.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110013113330053) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 198579626673 + ... + 198579627226.

It is an arithmetic number, because the mean of its divisors is an integer number (27602568146050).

Almost surely, 2^{110013113330023} is an apocalyptic number.

110013113330023 is a deficient number, since it is larger than the sum of its proper divisors (397159254177).

110013113330023 is an equidigital number, since it uses as much as digits as its factorization.

110013113330023 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 397159254176.

The product of its (nonzero) digits is 486, while the sum is 22.

Adding to 110013113330023 its reverse (320033311310011), we get a palindrome (430046424640034).

The spelling of 110013113330023 in words is "one hundred ten trillion, thirteen billion, one hundred thirteen million, three hundred thirty thousand, twenty-three".