110013144411103 has 2 divisors, whose sum is σ = 110013144411104. Its totient is φ = 110013144411102.

The previous prime is 110013144411097. The next prime is 110013144411151. The reversal of 110013144411103 is 301114441310011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110013144411103 - 2³³ = 110004554476511 is a prime.

It is a super-4 number, since 4×110013144411103⁴ (a number of 57 digits) contains 4444 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110013144441103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006572205551 + 55006572205552.

It is an arithmetic number, because the mean of its divisors is an integer number (55006572205552).

Almost surely, 2^{110013144411103} is an apocalyptic number.

110013144411103 is a deficient number, since it is larger than the sum of its proper divisors (1).

110013144411103 is an equidigital number, since it uses as much as digits as its factorization.

110013144411103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 576, while the sum is 25.

Adding to 110013144411103 its reverse (301114441310011), we get a palindrome (411127585721114).

The spelling of 110013144411103 in words is "one hundred ten trillion, thirteen billion, one hundred forty-four million, four hundred eleven thousand, one hundred three".