1100132233483 has 2 divisors, whose sum is σ = 1100132233484. Its totient is φ = 1100132233482.

The previous prime is 1100132233477. The next prime is 1100132233493. The reversal of 1100132233483 is 3843322310011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100132233483 is a prime.

It is a super-2 number, since 2×1100132233483² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100132233493) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550066116741 + 550066116742.

It is an arithmetic number, because the mean of its divisors is an integer number (550066116742).

Almost surely, 2^{1100132233483} is an apocalyptic number.

1100132233483 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100132233483 is an equidigital number, since it uses as much as digits as its factorization.

1100132233483 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10368, while the sum is 31.

Adding to 1100132233483 its reverse (3843322310011), we get a palindrome (4943454543494).

The spelling of 1100132233483 in words is "one trillion, one hundred billion, one hundred thirty-two million, two hundred thirty-three thousand, four hundred eighty-three".