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110013310012303 is a prime number
BaseRepresentation
bin11001000000111001111000…
…010000111000101110001111
3112102112011120201200110111201
4121000321320100320232033
5103404424224330343203
61025551230015330331
732113125243664255
oct3100717020705617
9472464521613451
10110013310012303
1132065423508465
1210409396b209a7
134950297968299
141d2495b9285d5
15caba72e9ee1d
hex640e78438b8f

110013310012303 has 2 divisors, whose sum is σ = 110013310012304. Its totient is φ = 110013310012302.

The previous prime is 110013310012283. The next prime is 110013310012379. The reversal of 110013310012303 is 303210013310011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 110013310012303 - 25 = 110013310012271 is a prime.

It is a super-2 number, since 2×1100133100123032 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110013310012393) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006655006151 + 55006655006152.

It is an arithmetic number, because the mean of its divisors is an integer number (55006655006152).

Almost surely, 2110013310012303 is an apocalyptic number.

110013310012303 is a deficient number, since it is larger than the sum of its proper divisors (1).

110013310012303 is an equidigital number, since it uses as much as digits as its factorization.

110013310012303 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 110013310012303 its reverse (303210013310011), we get a palindrome (413223323322314).

The spelling of 110013310012303 in words is "one hundred ten trillion, thirteen billion, three hundred ten million, twelve thousand, three hundred three".