110013312113 has 2 divisors, whose sum is σ = 110013312114. Its totient is φ = 110013312112.

The previous prime is 110013312107. The next prime is 110013312133. The reversal of 110013312113 is 311213310011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 93631104064 + 16382208049 = 305992^2 + 127993^2 .

It is a cyclic number.

It is not a de Polignac number, because 110013312113 - 2¹⁸ = 110013049969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110013312091 and 110013312100.

It is not a weakly prime, because it can be changed into another prime (110013312133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55006656056 + 55006656057.

It is an arithmetic number, because the mean of its divisors is an integer number (55006656057).

Almost surely, 2^110013312113 is an apocalyptic number.

It is an amenable number.

110013312113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110013312113 is an equidigital number, since it uses as much as digits as its factorization.

110013312113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 110013312113 its reverse (311213310011), we get a palindrome (421226622124).

The spelling of 110013312113 in words is "one hundred ten billion, thirteen million, three hundred twelve thousand, one hundred thirteen".