110013324334042 has 4 divisors (see below), whose sum is σ = 165019986501066. Its totient is φ = 55006662167020.

The previous prime is 110013324334021. The next prime is 110013324334063. The reversal of 110013324334042 is 240433423310011.

It is a semiprime because it is the product of two primes.

It is an interprime number because it is at equal distance from previous prime (110013324334021) and next prime (110013324334063).

It can be written as a sum of positive squares in only one way, i.e., 85856698960321 + 24156625373721 = 9265889^2 + 4914939^2 .

It is a super-3 number, since 3×110013324334042³ (a number of 43 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110013324333995 and 110013324334013.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27503331083509 + ... + 27503331083512.

Almost surely, 2^{110013324334042} is an apocalyptic number.

110013324334042 is a deficient number, since it is larger than the sum of its proper divisors (55006662167024).

110013324334042 is an equidigital number, since it uses as much as digits as its factorization.

110013324334042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55006662167023.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 110013324334042 its reverse (240433423310011), we get a palindrome (350446747644053).

The spelling of 110013324334042 in words is "one hundred ten trillion, thirteen billion, three hundred twenty-four million, three hundred thirty-four thousand, forty-two".