Base | Representation |
---|---|
bin | 110011001110101001… |
… | …1110111101110011111 |
3 | 101111222000122111100010 |
4 | 1212131103313232133 |
5 | 3300301413224203 |
6 | 122312305134303 |
7 | 10643143410132 |
oct | 1463523675637 |
9 | 344860574303 |
10 | 110013414303 |
11 | 42724782511 |
12 | 193a332a393 |
13 | a4b3215870 |
14 | 5478cb6219 |
15 | 2cdd397303 |
hex | 199d4f7b9f |
110013414303 has 16 divisors (see below), whose sum is σ = 159501655040. Its totient is φ = 67043273184.
The previous prime is 110013414299. The next prime is 110013414373. The reversal of 110013414303 is 303414310011.
It is not a de Polignac number, because 110013414303 - 22 = 110013414299 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 110013414303.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (110013414373) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 13689463 + ... + 13697496.
It is an arithmetic number, because the mean of its divisors is an integer number (9968853440).
Almost surely, 2110013414303 is an apocalyptic number.
110013414303 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
110013414303 is a deficient number, since it is larger than the sum of its proper divisors (49488240737).
110013414303 is a wasteful number, since it uses less digits than its factorization.
110013414303 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 27387078.
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 110013414303 its reverse (303414310011), we get a palindrome (413427724314).
The spelling of 110013414303 in words is "one hundred ten billion, thirteen million, four hundred fourteen thousand, three hundred three".
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