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110014102534343 = 7212661011773307
BaseRepresentation
bin11001000000111010100111…
…100000000111100011000111
3112102112020121221221202100212
4121000322213200013203013
5103404432340222044333
61025551440410030035
732113154006214200
oct3100724740074307
9472466557852325
10110014102534343
113206579a900a57
121040957841831b
134950392c00537
141d249d4ca85a7
15cababc84b448
hex640ea78078c7

110014102534343 has 12 divisors (see below), whose sum is σ = 127975761908712. Its totient is φ = 94297674517200.

The previous prime is 110014102534307. The next prime is 110014102534489. The reversal of 110014102534343 is 343435201410011.

It is not a de Polignac number, because 110014102534343 - 212 = 110014102530247 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (110014102534543) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 61152296 + ... + 62925602.

It is an arithmetic number, because the mean of its divisors is an integer number (10664646825726).

Almost surely, 2110014102534343 is an apocalyptic number.

110014102534343 is a deficient number, since it is larger than the sum of its proper divisors (17961659374369).

110014102534343 is a wasteful number, since it uses less digits than its factorization.

110014102534343 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3039422 (or 3039415 counting only the distinct ones).

The product of its (nonzero) digits is 17280, while the sum is 32.

Adding to 110014102534343 its reverse (343435201410011), we get a palindrome (453449303944354).

The spelling of 110014102534343 in words is "one hundred ten trillion, fourteen billion, one hundred two million, five hundred thirty-four thousand, three hundred forty-three".

Divisors: 1 7 49 1266101 1773307 8862707 12413149 62038949 86892043 2245185766007 15716300362049 110014102534343