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110014142422213 is a prime number
BaseRepresentation
bin11001000000111010101001…
…111000010001110011000101
3112102112020201202000021020101
4121000322221320101303011
5103404432430430002323
61025551444353004101
732113155002234311
oct3100725170216305
9472466652007211
10110014142422213
1132065810375337
1210409589853631
13495039b258023
141d249da2ccb41
15cabac10c9dad
hex640ea9e11cc5

110014142422213 has 2 divisors, whose sum is σ = 110014142422214. Its totient is φ = 110014142422212.

The previous prime is 110014142422201. The next prime is 110014142422273. The reversal of 110014142422213 is 312224241410011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 58398222948129 + 51615919474084 = 7641873^2 + 7184422^2 .

It is a cyclic number.

It is not a de Polignac number, because 110014142422213 - 25 = 110014142422181 is a prime.

It is a super-2 number, since 2×1100141424222132 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110014142422273) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55007071211106 + 55007071211107.

It is an arithmetic number, because the mean of its divisors is an integer number (55007071211107).

Almost surely, 2110014142422213 is an apocalyptic number.

It is an amenable number.

110014142422213 is a deficient number, since it is larger than the sum of its proper divisors (1).

110014142422213 is an equidigital number, since it uses as much as digits as its factorization.

110014142422213 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3072, while the sum is 28.

Adding to 110014142422213 its reverse (312224241410011), we get a palindrome (422238383832224).

The spelling of 110014142422213 in words is "one hundred ten trillion, fourteen billion, one hundred forty-two million, four hundred twenty-two thousand, two hundred thirteen".