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110020001012002 = 255010000506001
BaseRepresentation
bin11001000001000000000111…
…000101000001100100100010
3112102112210212000222110120101
4121001000013011001210202
5103410031430224341002
61025554253554533014
732113453121360104
oct3101000705014442
9472483760873511
10110020001012002
11320682473a0584
121040a74389716a
134950ac2c418c3
141d24dd440b574
15cabd155cd587
hex641007141922

110020001012002 has 4 divisors (see below), whose sum is σ = 165030001518006. Its totient is φ = 55010000506000.

The previous prime is 110020001011867. The next prime is 110020001012027. The reversal of 110020001012002 is 200210100020011.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 110017212010281 + 2789001721 = 10488909^2 + 52811^2 .

It is a super-2 number, since 2×1100200010120022 (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 110020001012002.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27505000252999 + ... + 27505000253002.

Almost surely, 2110020001012002 is an apocalyptic number.

110020001012002 is a deficient number, since it is larger than the sum of its proper divisors (55010000506004).

110020001012002 is an equidigital number, since it uses as much as digits as its factorization.

110020001012002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 55010000506003.

The product of its (nonzero) digits is 8, while the sum is 10.

Adding to 110020001012002 its reverse (200210100020011), we get a palindrome (310230101032013).

The spelling of 110020001012002 in words is "one hundred ten trillion, twenty billion, one million, twelve thousand, two".

Divisors: 1 2 55010000506001 110020001012002