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110020102212193 is a prime number
BaseRepresentation
bin11001000001000000001101…
…000111000100101001100001
3112102112211010002101222010121
4121001000031013010221201
5103410032132131242233
61025554312012000241
732113455460511305
oct3101001507045141
9472484102358117
10110020102212193
11320682995317a8
121040a771760081
134950b0abb5784
141d25003a31d05
15cabd1e41d92d
hex64100d1c4a61

110020102212193 has 2 divisors, whose sum is σ = 110020102212194. Its totient is φ = 110020102212192.

The previous prime is 110020102212191. The next prime is 110020102212233. The reversal of 110020102212193 is 391212201020011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 100701686610529 + 9318415601664 = 10035023^2 + 3052608^2 .

It is a cyclic number.

It is not a de Polignac number, because 110020102212193 - 21 = 110020102212191 is a prime.

It is a super-3 number, since 3×1100201022121933 (a number of 43 digits) contains 333 as substring.

Together with 110020102212191, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (110020102212191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010051106096 + 55010051106097.

It is an arithmetic number, because the mean of its divisors is an integer number (55010051106097).

Almost surely, 2110020102212193 is an apocalyptic number.

It is an amenable number.

110020102212193 is a deficient number, since it is larger than the sum of its proper divisors (1).

110020102212193 is an equidigital number, since it uses as much as digits as its factorization.

110020102212193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 432, while the sum is 25.

The spelling of 110020102212193 in words is "one hundred ten trillion, twenty billion, one hundred two million, two hundred twelve thousand, one hundred ninety-three".