Base | Representation |
---|---|
bin | 10000000000101001000… |
… | …110001101010100111011 |
3 | 10220011210220111202222202 |
4 | 100000221012031110323 |
5 | 121011202441333313 |
6 | 2201231520140415 |
7 | 142326003141251 |
oct | 20005106152473 |
9 | 3804726452882 |
10 | 1100201121083 |
11 | 39465793a269 |
12 | 15928716770b |
13 | 7c99666592c |
14 | 3b37009c5d1 |
15 | 1d94347c558 |
hex | 1002918d53b |
1100201121083 has 2 divisors, whose sum is σ = 1100201121084. Its totient is φ = 1100201121082.
The previous prime is 1100201121079. The next prime is 1100201121101. The reversal of 1100201121083 is 3801211020011.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100201121083 - 22 = 1100201121079 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100201121013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100560541 + 550100560542.
It is an arithmetic number, because the mean of its divisors is an integer number (550100560542).
Almost surely, 21100201121083 is an apocalyptic number.
1100201121083 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100201121083 is an equidigital number, since it uses as much as digits as its factorization.
1100201121083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 96, while the sum is 20.
Adding to 1100201121083 its reverse (3801211020011), we get a palindrome (4901412141094).
The spelling of 1100201121083 in words is "one trillion, one hundred billion, two hundred one million, one hundred twenty-one thousand, eighty-three".
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