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11002011433 = 74336551533
BaseRepresentation
bin10100011111100010…
…10101111100101001
31001101202020002101221
422033301111330221
5140013003331213
65015415142041
7536432361040
oct121761257451
931352202357
1011002011433
114736392036
122170674921
13106448004a
14765275557
15445d3a38d
hex28fc55f29

11002011433 has 8 divisors (see below), whose sum is σ = 12866139968. Its totient is φ = 9210986064.

The previous prime is 11002011407. The next prime is 11002011451. The reversal of 11002011433 is 33411020011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a de Polignac number, because none of the positive numbers 2k-11002011433 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (11002011233) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 18275466 + ... + 18276067.

It is an arithmetic number, because the mean of its divisors is an integer number (1608267496).

Almost surely, 211002011433 is an apocalyptic number.

It is an amenable number.

11002011433 is a deficient number, since it is larger than the sum of its proper divisors (1864128535).

11002011433 is an equidigital number, since it uses as much as digits as its factorization.

11002011433 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 36551583.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 11002011433 its reverse (33411020011), we get a palindrome (44413031444).

The spelling of 11002011433 in words is "eleven billion, two million, eleven thousand, four hundred thirty-three".

Divisors: 1 7 43 301 36551533 255860731 1571715919 11002011433