1100201303081 has 2 divisors, whose sum is σ = 1100201303082. Its totient is φ = 1100201303080.

The previous prime is 1100201303063. The next prime is 1100201303099. The reversal of 1100201303081 is 1803031020011.

It is a balanced prime because it is at equal distance from previous prime (1100201303063) and next prime (1100201303099).

It can be written as a sum of positive squares in only one way, i.e., 852037917481 + 248163385600 = 923059^2 + 498160^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100201303081 - 2²⁶ = 1100134194217 is a prime.

It is a super-3 number, since 3×1100201303081³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1100201303281) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100651540 + 550100651541.

It is an arithmetic number, because the mean of its divisors is an integer number (550100651541).

Almost surely, 2^{1100201303081} is an apocalyptic number.

It is an amenable number.

1100201303081 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100201303081 is an equidigital number, since it uses as much as digits as its factorization.

1100201303081 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 1100201303081 its reverse (1803031020011), we get a palindrome (2903232323092).

The spelling of 1100201303081 in words is "one trillion, one hundred billion, two hundred one million, three hundred three thousand, eighty-one".