110020130317 has 2 divisors, whose sum is σ = 110020130318. Its totient is φ = 110020130316.

The previous prime is 110020130303. The next prime is 110020130359. The reversal of 110020130317 is 713031020011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 85665094596 + 24355035721 = 292686^2 + 156061^2 .

It is a cyclic number.

It is not a de Polignac number, because 110020130317 - 2¹⁵ = 110020097549 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110020130294 and 110020130303.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (110020130387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010065158 + 55010065159.

It is an arithmetic number, because the mean of its divisors is an integer number (55010065159).

Almost surely, 2^110020130317 is an apocalyptic number.

It is an amenable number.

110020130317 is a deficient number, since it is larger than the sum of its proper divisors (1).

110020130317 is an equidigital number, since it uses as much as digits as its factorization.

110020130317 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 19.

Adding to 110020130317 its reverse (713031020011), we get a palindrome (823051150328).

The spelling of 110020130317 in words is "one hundred ten billion, twenty million, one hundred thirty thousand, three hundred seventeen".