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1100201311351 is a prime number
BaseRepresentation
bin10000000000101001000…
…110111011110001110111
310220011210220212102222201
4100000221012323301313
5121011203013430401
62201231524205331
7142326004563052
oct20005106736167
93804726772881
101100201311351
11394657a5a20a
12159287239847
137c99670140c
143b37010ba99
151d9434b8b01
hex100291bbc77

1100201311351 has 2 divisors, whose sum is σ = 1100201311352. Its totient is φ = 1100201311350.

The previous prime is 1100201311303. The next prime is 1100201311361. The reversal of 1100201311351 is 1531131020011.

It is a strong prime.

It is an emirp because it is prime and its reverse (1531131020011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100201311351 - 211 = 1100201309303 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100201311361) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100655675 + 550100655676.

It is an arithmetic number, because the mean of its divisors is an integer number (550100655676).

Almost surely, 21100201311351 is an apocalyptic number.

1100201311351 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100201311351 is an equidigital number, since it uses as much as digits as its factorization.

1100201311351 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 90, while the sum is 19.

Adding to 1100201311351 its reverse (1531131020011), we get a palindrome (2631332331362).

The spelling of 1100201311351 in words is "one trillion, one hundred billion, two hundred one million, three hundred eleven thousand, three hundred fifty-one".