Base | Representation |
---|---|
bin | 10000000000101001000… |
… | …111000011000101011001 |
3 | 10220011210220220222000221 |
4 | 100000221013003011121 |
5 | 121011203020410043 |
6 | 2201231525000041 |
7 | 142326005046226 |
oct | 20005107030531 |
9 | 3804726828027 |
10 | 1100201341273 |
11 | 394657a7a741 |
12 | 159287253021 |
13 | 7c996711c18 |
14 | 3b37011894d |
15 | 1d9434c28ed |
hex | 100291c3159 |
1100201341273 has 2 divisors, whose sum is σ = 1100201341274. Its totient is φ = 1100201341272.
The previous prime is 1100201341271. The next prime is 1100201341279. The reversal of 1100201341273 is 3721431020011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 856019095369 + 244182245904 = 925213^2 + 494148^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100201341273 - 21 = 1100201341271 is a prime.
Together with 1100201341271, it forms a pair of twin primes.
It is not a weakly prime, because it can be changed into another prime (1100201341271) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100670636 + 550100670637.
It is an arithmetic number, because the mean of its divisors is an integer number (550100670637).
Almost surely, 21100201341273 is an apocalyptic number.
It is an amenable number.
1100201341273 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100201341273 is an equidigital number, since it uses as much as digits as its factorization.
1100201341273 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1008, while the sum is 25.
Adding to 1100201341273 its reverse (3721431020011), we get a palindrome (4821632361284).
The spelling of 1100201341273 in words is "one trillion, one hundred billion, two hundred one million, three hundred forty-one thousand, two hundred seventy-three".
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