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1100201341273 is a prime number
BaseRepresentation
bin10000000000101001000…
…111000011000101011001
310220011210220220222000221
4100000221013003011121
5121011203020410043
62201231525000041
7142326005046226
oct20005107030531
93804726828027
101100201341273
11394657a7a741
12159287253021
137c996711c18
143b37011894d
151d9434c28ed
hex100291c3159

1100201341273 has 2 divisors, whose sum is σ = 1100201341274. Its totient is φ = 1100201341272.

The previous prime is 1100201341271. The next prime is 1100201341279. The reversal of 1100201341273 is 3721431020011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 856019095369 + 244182245904 = 925213^2 + 494148^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100201341273 - 21 = 1100201341271 is a prime.

Together with 1100201341271, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1100201341271) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550100670636 + 550100670637.

It is an arithmetic number, because the mean of its divisors is an integer number (550100670637).

Almost surely, 21100201341273 is an apocalyptic number.

It is an amenable number.

1100201341273 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100201341273 is an equidigital number, since it uses as much as digits as its factorization.

1100201341273 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 1100201341273 its reverse (3721431020011), we get a palindrome (4821632361284).

The spelling of 1100201341273 in words is "one trillion, one hundred billion, two hundred one million, three hundred forty-one thousand, two hundred seventy-three".