Base | Representation |
---|---|
bin | 10000000000101001001… |
… | …001100011111010011111 |
3 | 10220011210222011102200101 |
4 | 100000221021203322133 |
5 | 121011203203000111 |
6 | 2201231551041531 |
7 | 142326013461631 |
oct | 20005111437237 |
9 | 3804728142611 |
10 | 1100202000031 |
11 | 39465838a672 |
12 | 1592875102a7 |
13 | 7c9968b2a14 |
14 | 3b37024aa51 |
15 | 1d9435a2bc1 |
hex | 10029263e9f |
1100202000031 has 2 divisors, whose sum is σ = 1100202000032. Its totient is φ = 1100202000030.
The previous prime is 1100202000017. The next prime is 1100202000047. The reversal of 1100202000031 is 1300002020011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100202000031 - 225 = 1100168445599 is a prime.
It is a super-2 number, since 2×11002020000312 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1100201999981 and 1100202000017.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100202000431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550101000015 + 550101000016.
It is an arithmetic number, because the mean of its divisors is an integer number (550101000016).
Almost surely, 21100202000031 is an apocalyptic number.
1100202000031 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100202000031 is an equidigital number, since it uses as much as digits as its factorization.
1100202000031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12, while the sum is 10.
Adding to 1100202000031 its reverse (1300002020011), we get a palindrome (2400204020042).
The spelling of 1100202000031 in words is "one trillion, one hundred billion, two hundred two million, thirty-one", and thus it is an aban number.
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