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11002022313 = 3197169910957
BaseRepresentation
bin10100011111100010…
…11000100110101001
31001101202020122022220
422033301120212221
5140013004203223
65015415304253
7536432434542
oct121761304651
931352218286
1011002022313
11473639a227
12217067b089
131064484c99
147652794c9
15445d3d6e3
hex28fc589a9

11002022313 has 16 divisors (see below), whose sum is σ = 14753851200. Its totient is φ = 7292488896.

The previous prime is 11002022263. The next prime is 11002022327. The reversal of 11002022313 is 31322020011.

11002022313 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a de Polignac number, because none of the positive numbers 2k-11002022313 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11002022292 and 11002022301.

It is not an unprimeable number, because it can be changed into a prime (11002023313) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 998631 + ... + 1009587.

It is an arithmetic number, because the mean of its divisors is an integer number (922115700).

Almost surely, 211002022313 is an apocalyptic number.

It is an amenable number.

11002022313 is a deficient number, since it is larger than the sum of its proper divisors (3751828887).

11002022313 is a wasteful number, since it uses less digits than its factorization.

11002022313 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 12856.

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 11002022313 its reverse (31322020011), we get a palindrome (42324042324).

The spelling of 11002022313 in words is "eleven billion, two million, twenty-two thousand, three hundred thirteen".

Divisors: 1 3 197 591 1699 5097 10957 32871 334703 1004109 2158529 6475587 18615943 55847829 3667340771 11002022313