Base | Representation |
---|---|
bin | 10100011111100010… |
… | …11111011001001111 |
3 | 1001101202022001111001 |
4 | 22033301133121033 |
5 | 140013011101002 |
6 | 5015420041131 |
7 | 536432611615 |
oct | 121761373117 |
9 | 31352261431 |
10 | 11002050127 |
11 | 4736409112 |
12 | 21706931a7 |
13 | 1064494843 |
14 | 7652856b5 |
15 | 445d46a87 |
hex | 28fc5f64f |
11002050127 has 2 divisors, whose sum is σ = 11002050128. Its totient is φ = 11002050126.
The previous prime is 11002050107. The next prime is 11002050139. The reversal of 11002050127 is 72105020011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 11002050127 - 27 = 11002049999 is a prime.
It is a super-2 number, since 2×110020501272 (a number of 21 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11002050107) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501025063 + 5501025064.
It is an arithmetic number, because the mean of its divisors is an integer number (5501025064).
Almost surely, 211002050127 is an apocalyptic number.
11002050127 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002050127 is an equidigital number, since it uses as much as digits as its factorization.
11002050127 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 140, while the sum is 19.
Adding to 11002050127 its reverse (72105020011), we get a palindrome (83107070138).
The spelling of 11002050127 in words is "eleven billion, two million, fifty thousand, one hundred twenty-seven".
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