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11002100221997 is a prime number
BaseRepresentation
bin1010000000011010000001…
…0001101000100000101101
31102221210100021121000021022
42200012200101220200231
52420224300124100442
635222143422343525
72213606204603453
oct240064021504055
942853307530238
1011002100221997
113561a67829875
12129834512aba5
1361a65558bc71
142a070c47c9d3
151412cac673d2
hexa01a046882d

11002100221997 has 2 divisors, whose sum is σ = 11002100221998. Its totient is φ = 11002100221996.

The previous prime is 11002100221921. The next prime is 11002100222107. The reversal of 11002100221997 is 79912200120011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 6251505090601 + 4750595131396 = 2500301^2 + 2179586^2 .

It is a cyclic number.

It is not a de Polignac number, because 11002100221997 - 230 = 11001026480173 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (11002100221897) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501050110998 + 5501050110999.

It is an arithmetic number, because the mean of its divisors is an integer number (5501050110999).

Almost surely, 211002100221997 is an apocalyptic number.

It is an amenable number.

11002100221997 is a deficient number, since it is larger than the sum of its proper divisors (1).

11002100221997 is an equidigital number, since it uses as much as digits as its factorization.

11002100221997 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 4536, while the sum is 35.

The spelling of 11002100221997 in words is "eleven trillion, two billion, one hundred million, two hundred twenty-one thousand, nine hundred ninety-seven".