Base | Representation |
---|---|
bin | 10000000000101001101… |
… | …011111110010110100111 |
3 | 10220011211121010202102121 |
4 | 100000221223332112213 |
5 | 121011213010134343 |
6 | 2201232512250411 |
7 | 142326153243526 |
oct | 20005153762647 |
9 | 3804747122377 |
10 | 1100211021223 |
11 | 3946624913a6 |
12 | 15928a540a07 |
13 | 7c998720bc2 |
14 | 3b3715184bd |
15 | 1d944285aed |
hex | 10029afe5a7 |
1100211021223 has 2 divisors, whose sum is σ = 1100211021224. Its totient is φ = 1100211021222.
The previous prime is 1100211021073. The next prime is 1100211021263. The reversal of 1100211021223 is 3221201120011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100211021223 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100211021197 and 1100211021206.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100211021263) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550105510611 + 550105510612.
It is an arithmetic number, because the mean of its divisors is an integer number (550105510612).
Almost surely, 21100211021223 is an apocalyptic number.
1100211021223 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100211021223 is an equidigital number, since it uses as much as digits as its factorization.
1100211021223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1100211021223 its reverse (3221201120011), we get a palindrome (4321412141234).
The spelling of 1100211021223 in words is "one trillion, one hundred billion, two hundred eleven million, twenty-one thousand, two hundred twenty-three".
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