Base | Representation |
---|---|
bin | 10000000000101001101… |
… | …011111110100010111101 |
3 | 10220011211121010210111212 |
4 | 100000221223332202331 |
5 | 121011213010201023 |
6 | 2201232512254205 |
7 | 142326153246035 |
oct | 20005153764275 |
9 | 3804747123455 |
10 | 1100211022013 |
11 | 394662491a54 |
12 | 15928a541365 |
13 | 7c99872137c |
14 | 3b3715188c5 |
15 | 1d944285e78 |
hex | 10029afe8bd |
1100211022013 has 2 divisors, whose sum is σ = 1100211022014. Its totient is φ = 1100211022012.
The previous prime is 1100211021989. The next prime is 1100211022039. The reversal of 1100211022013 is 3102201120011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 971569005124 + 128642016889 = 985682^2 + 358667^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100211022013 - 210 = 1100211020989 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1100211022063) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550105511006 + 550105511007.
It is an arithmetic number, because the mean of its divisors is an integer number (550105511007).
Almost surely, 21100211022013 is an apocalyptic number.
It is an amenable number.
1100211022013 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100211022013 is an equidigital number, since it uses as much as digits as its factorization.
1100211022013 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 24, while the sum is 14.
Adding to 1100211022013 its reverse (3102201120011), we get a palindrome (4202412142024).
The spelling of 1100211022013 in words is "one trillion, one hundred billion, two hundred eleven million, twenty-two thousand, thirteen".
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