Base | Representation |
---|---|
bin | 10000000000101001101… |
… | …100101111001000111011 |
3 | 10220011211121111220112122 |
4 | 100000221230233020323 |
5 | 121011213033033201 |
6 | 2201232520431455 |
7 | 142326155035235 |
oct | 20005154571073 |
9 | 3804747456478 |
10 | 1100211221051 |
11 | 394662608548 |
12 | 15928a61858b |
13 | 7c998790b47 |
14 | 3b37156b255 |
15 | 1d9442c4e1b |
hex | 10029b2f23b |
1100211221051 has 2 divisors, whose sum is σ = 1100211221052. Its totient is φ = 1100211221050.
The previous prime is 1100211221047. The next prime is 1100211221089. The reversal of 1100211221051 is 1501221120011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100211221051 - 22 = 1100211221047 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100210221051) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550105610525 + 550105610526.
It is an arithmetic number, because the mean of its divisors is an integer number (550105610526).
Almost surely, 21100211221051 is an apocalyptic number.
1100211221051 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100211221051 is an equidigital number, since it uses as much as digits as its factorization.
1100211221051 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 40, while the sum is 17.
Adding to 1100211221051 its reverse (1501221120011), we get a palindrome (2601432341062).
The spelling of 1100211221051 in words is "one trillion, one hundred billion, two hundred eleven million, two hundred twenty-one thousand, fifty-one".
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