Base | Representation |
---|---|
bin | 1010000000011010000100… |
… | …0010111000000111111011 |
3 | 1102221210101011212212002122 |
4 | 2200012201002320013323 |
5 | 2420224311430143003 |
6 | 35222145003151455 |
7 | 2213606422410161 |
oct | 240064102700773 |
9 | 42853334785078 |
10 | 11002113131003 |
11 | 3561a74046575 |
12 | 129834951558b |
13 | 61a65815b927 |
14 | 2a071007d231 |
15 | 1412cbe67238 |
hex | a01a10b81fb |
11002113131003 has 2 divisors, whose sum is σ = 11002113131004. Its totient is φ = 11002113131002.
The previous prime is 11002113130993. The next prime is 11002113131059. The reversal of 11002113131003 is 30013131120011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11002113131003 - 220 = 11002112082427 is a prime.
It is not a weakly prime, because it can be changed into another prime (11002113131903) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5501056565501 + 5501056565502.
It is an arithmetic number, because the mean of its divisors is an integer number (5501056565502).
Almost surely, 211002113131003 is an apocalyptic number.
11002113131003 is a deficient number, since it is larger than the sum of its proper divisors (1).
11002113131003 is an equidigital number, since it uses as much as digits as its factorization.
11002113131003 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11002113131003 its reverse (30013131120011), we get a palindrome (41015244251014).
The spelling of 11002113131003 in words is "eleven trillion, two billion, one hundred thirteen million, one hundred thirty-one thousand, three".
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