110021133113 has 4 divisors (see below), whose sum is σ = 111824758308. Its totient is φ = 108217507920.

The previous prime is 110021133097. The next prime is 110021133119. The reversal of 110021133113 is 311331120011.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311331120011 = 185477 ⋅1678543.

It can be written as a sum of positive squares in 2 ways, for example, as 30608202304 + 79412930809 = 174952^2 + 281803^2 .

It is a cyclic number.

It is not a de Polignac number, because 110021133113 - 2⁴ = 110021133097 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 110021133091 and 110021133100.

It is not an unprimeable number, because it can be changed into a prime (110021133119) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 901812506 + ... + 901812627.

It is an arithmetic number, because the mean of its divisors is an integer number (27956189577).

Almost surely, 2^110021133113 is an apocalyptic number.

It is an amenable number.

110021133113 is a deficient number, since it is larger than the sum of its proper divisors (1803625195).

110021133113 is an equidigital number, since it uses as much as digits as its factorization.

110021133113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1803625194.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 110021133113 its reverse (311331120011), we get a palindrome (421352253124).

The spelling of 110021133113 in words is "one hundred ten billion, twenty-one million, one hundred thirty-three thousand, one hundred thirteen".