Base | Representation |
---|---|
bin | 11001000001000001001011… |
… | …000010111101010101011011 |
3 | 112102112220210111200011111212 |
4 | 121001001023002331111123 |
5 | 103410041244134233201 |
6 | 1025555003051413335 |
7 | 32113523306006222 |
oct | 3101011302752533 |
9 | 472486714604455 |
10 | 110021141321051 |
11 | 32068782037654 |
12 | 1040aa0175424b |
13 | 4950c4526699c |
14 | 1d250a1a3dcb9 |
15 | cabd80777abb |
hex | 64104b0bd55b |
110021141321051 has 2 divisors, whose sum is σ = 110021141321052. Its totient is φ = 110021141321050.
The previous prime is 110021141321011. The next prime is 110021141321087. The reversal of 110021141321051 is 150123141120011.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-110021141321051 is a prime.
It is not a weakly prime, because it can be changed into another prime (110021141321011) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55010570660525 + 55010570660526.
It is an arithmetic number, because the mean of its divisors is an integer number (55010570660526).
Almost surely, 2110021141321051 is an apocalyptic number.
110021141321051 is a deficient number, since it is larger than the sum of its proper divisors (1).
110021141321051 is an equidigital number, since it uses as much as digits as its factorization.
110021141321051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 240, while the sum is 23.
Adding to 110021141321051 its reverse (150123141120011), we get a palindrome (260144282441062).
The spelling of 110021141321051 in words is "one hundred ten trillion, twenty-one billion, one hundred forty-one million, three hundred twenty-one thousand, fifty-one".
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